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3. A cylinder contains 36.0 grams he gas, 140.0 grams N2 gas and 264.0 grams CO2. Compute the mole fraction of helium. The total pressure of the cylinder is given as 15.0 atm. Compute the partial pressure of the gas in atm.

Respuesta :

Answer:

Explanation:

1 mole of He is 4 gm

36 gm of He is 36/4=9 moles of He

1 mole of N2 is 14X2=28 gm

140 gm of N2 is 140/28 =5 moles

1 mole of CO2 is (12 + 16x20) = 44 gm

264 gm CO2 = 264/44 =6 MOLES

TOTAL MOLES IS 9 + 5 +6 = 20 MOLES

MOLE FRACTION OF He IS 9/20

total pressure due to all of the moles is 15 ATM

  1. THE PARTIAL PRESSURE DUE TO He MOLES IS (9/20) x 15 ATM =

(3/4)x9 =27/4 =6.75 atm

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