Saturn has an orbital period of 29.46 years. In two or more sentences, explain how to calculate the average distance from Saturn to the sun and then calculate it.

Respuesta :

Keplers 3rd law tells us that the square of the orbital period of a planet is proportional to the cube of the semi-major axis if the planet.

p^2 = a^3

So if the orbital period is 29.46 years, then:

(29.46)^2 = a^3

867.8916 = a^3

9.54 au = a

So the average distance between Saturn and the Sun is 9.54 au

au = atronomical units. 

idk if i did this right, its been a while


Answer:

9.54 AU

Explanation:

Kepler's Third law of motion would be used. According to it, the square of orbital period (P) is proportional to the cube of average distance (a).

P² = a³

where, P is in years and a is in AU.

Given P = 29.46 years

Substitute the values as follows:

(29.46)² = a³

[tex]\Rightarrow a= \sqrt[3]{867.9}=9.54 AU[/tex]

Thus, the average distance between the Sun and Saturn is 9.54 AU.