We want to see for which values of x does the rational expression make sense. We will see that the expression makes sense for x ≤ 0
We know that the argument of a square root can only be a real number equal to or larger than zero.
In this case, we have the expression:
[tex]\sqrt{(-2x)^2} = (\sqrt{-2x} )^2[/tex]
One would want to directly cancel the square root with the 2 exponent, but we can't do that, because in the right-side expression we would have a complex number if the argument is smaller than zero.
The first thing we need to do is to make the argument equal or larger than zero:
-2x ≥ 0
x ≤ 0/-2
x ≤ 0
So the given expression only makes sense for x ≤ 0
If you want to learn more about rational expressions, you can read:
https://brainly.com/question/18545256
