The function that gives the surface area has the radius as a denominator.
Reasons:
The given parameter are;
The expression Clare finds is the surface area for a fixed volume in terms of the radius, r, is S(r)
The function is used to plot the graph
The values r are allowed to take (obtained from a similar question are) = -1, 2, and 3
The graph of a similar function representing the surface area is attached;
[tex]\displaystyle S(r) = \mathbf{2 \cdot \pi \cdot r^2 + \frac{2 \cdot \pi }{r}}[/tex]
From the graph, it is observed that there is a vertical asymptote at x = 0 (infinite discontinuity)
Therefore, Claire should use the a domain that gives a continuous graph,
given that r is a denominator of the function, by allowing the radius, r to
take on only natural number values (values larger than 0)
The domain is therefore; 0 < r < ∞
The values r can take should therefore be 0.1, 1, 2, and 3
Learn more about asymptotes here:
https://brainly.com/question/17257427
