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A car of mass 1,000 kg begins stationary on a road at the top of a
mountain, at a height h = 3,000 m. The car then rolls freely down a
winding road, travelling a total distance of 5 km, to reach the height h
= 2,000 m. Assume g = 9.8 ms 2.
1
How much energy did the car lose on descent? Give you answer to 3 significant figures,
with units.
Energy lost =

Respuesta :

Eduard22sly

The energy lost by the car on descent is 980×10⁴ J

We'll begin by calculating the energy of car at various heights.

At height 3000 m:

Mass (m) = 1000 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) = 3000 m

Energy (E) =?

E = mgh

E = 1000 × 9.8 × 3000

E = 29400000 J

At height 2000 m:

Mass (m) = 1000 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) = 2000 m

Energy (E) =?

E = mgh

E = 1000 × 9.8 × 2000

E = 19600000 J

Finally, we shall determine the the energy lost

Energy at 3000 m = 29400000 J

Energy at 2000 m = 19600000 J

Energy lost =?

Energy lost = Energy at 3000 m – Energy at 2000 m

Energy lost = 29400000 – 19600000

Energy lost = 980×10⁴ J

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