Answer:
x = -1, -5
Step-by-step explanation:
[tex] {(x + 3)}^{2} = 4 \\ = > {x}^{2} + 2 \times x \times 3 + {3}^{2} = 4 \\ = > {x}^{2} + 6x + 9 = 4 \\ = > {x}^{2} + 6x = 4 - 9 \\ = > {x}^{2} + 6x = - 5 \\ = > {x}^{2} + 6x + 5 = 0 \\ = > {x}^{2} + 5x + x + 5 = 0 \\ = > x(x + 5) + 1(x + 5) = 0 \\ = > (x + 1)(x + 5) \\ = > x = - 1 \: \: or \: \: - 5[/tex]
Hope it helps.
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