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Problem 1.1
The owner of a new restaurant is ordering tables and
chairs. She wants to have only tables for 2 and tables
for 4.
The total number of people that can be seated in the
restaurant is 120.
Describe some possible combinations of 2-seat tables
and 4-seat tables that will seat 120 customers.
Tables for 2
Tables for 4
0
30.

Respuesta :

s1m1

Answer:

Step-by-step explanation:

1 table and 2 chairs (2-seat table)

1 table and 4 chairs (4-seat table)

120 people so we need 120 chairs

Some Possibilities  :

120 /4 = 30

0( 2-seat table) and 30 (4- seat tables) because 0·2 + 30·4 = 0+120 = 120

2( 2-seat table) and 29 (4- seat tables) because 2·2 + 29·4 = 4+ 116= 120

4( 2-seat table) and 28 (4- seat tables) because 4·2 + 28·4 = 8+ 112= 120

...

120/2 = 60

60( 2-seat table) and 0 (4- seat tables) because 60·2 + 0·4 = 120 + 0 = 120

58( 2-seat table) and 1 (4- seat tables) because 58·2 + 1·4 = 116 + 4 = 120

56( 2-seat table) and 2 (4- seat tables) because 56·2 + 2·4 = 112 + 8 = 120

...

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