The mass of Fe obtained from the reaction is 0.0533 g
We'll begin by calculating the mass of Al that reacted and the mass of Fe produced from the balanced equation.
2Al + Fe₂O₃ —> 2Fe + Al₂O₃
Molar mass of Al = 27 g/mol
Mass of Al from the balanced equation = 2 × 27 = 54 g
Molar mass of Fe = 56 g/mol
Mass of Fe from the balanced equation = 2 × 56 = 112 g
From the balanced equation above,
54 g of Al reacted to produce 112 g of Fe.
From the balanced equation above,
54 g of Al reacted to produce 112 g of Fe.
Therefore,
0.0257 g of Al will react to produce = (0.0257 × 112) / 54 = 0.0533 g of Fe
Thus, 0.0533 g of Fe was obtained from the reaction.
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