[tex]\huge\color{pink}\boxed{\colorbox{black}{Answer ☘}}[/tex]
[tex]g(n) = - 2n - 4 \\ f(n) = 3n + 1[/tex]
[tex]g(n) \times f(n) = ( - 2n - 4)(3n + 1) \\ => -2n ( 3n + 1 ) -4 ( 3n + 1 ) \\ = > - 6n² - 2n - 12n - 4 \\ = > - 6n² - 14n - 4 \\ = > - (16n² + 14n + 4)[/tex]
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Answer:
g(n) * f(n) = -6n² -14n - 4
Step-by-step explanation:
Given the following function operations g(n) * f(n), where: g(n) = -2n - 4, and f(n) = 3n + 1:
We can express the product of both functions as follows:
( g · f )(n) = g(n) · f(n) = (-2n -4)(3n + 1)
Next, use the FOIL method:
( g · f )(n) = (-2n -4)(3n + 1) = -6n² -2n - 12n - 4
Combine like terms:
( g · f )(n) = -6n² -14n - 4
Therefore, g(n) * f(n) = -6n² -14n - 4.
