Answer:
7) m = 6
8) k = 15
9) a = -12
10) x = 1
11) n = 4
12) r = 11
Step-by-step explanation:
Solution :
Solving all the questions step by step!
7) 1 = 6+m/12
[tex] \longmapsto{\tt{1 = \dfrac{6 + m}{12}}}[/tex]
[tex] \longmapsto{\tt{6 + m = 1 \times 12}}[/tex]
[tex] \longmapsto{\tt{6 + m = 12}}[/tex]
[tex] \longmapsto{\tt{m = 12 - 6}}[/tex]
[tex] \longmapsto{\tt{m = 6}}[/tex]
[tex]\bigstar\: \:\underline{\boxed{\tt{\pink{m = 6}}}}[/tex]
- Hence, the value of m is 6.
[tex]\begin{gathered}\end{gathered}[/tex]
8) 8 = 3 + k/3
[tex]\implies{\tt{8 = 3 + \dfrac{k}{3}}}[/tex]
[tex]\implies{\tt{ \dfrac{k}{3} = 8 - 3}}[/tex]
[tex]\implies{\tt{ \dfrac{k}{3} = 5}}[/tex]
[tex]\implies{\tt{k = 5 \times 3}}[/tex]
[tex]\implies{\tt{k = 15}}[/tex]
[tex]\bigstar \: \: \underline{\boxed{\tt{\red{k = 15}}}}[/tex]
- Hence, the value of k is 15.
[tex]\begin{gathered}\end{gathered}[/tex]
9) -4(-8+a) = 80
[tex] \longmapsto{\tt{ - 4( - 8 + a) = 80}}[/tex]
[tex] \longmapsto{\tt{( - 8 + a) = \dfrac{80}{ - 4}}}[/tex]
[tex] \longmapsto{\tt{( - 8 + a) = - 20}}[/tex]
[tex] \longmapsto{\tt{a = - 20 - ( - 8)}}[/tex]
[tex] \longmapsto{\tt{a = - 20 + 8}}[/tex]
[tex] \longmapsto{\tt{a = -12}}[/tex]
[tex]\bigstar \: \: \underline{\boxed{\tt{\purple{a = - 12}}}}[/tex]
- Hence, the value of a is -12.
[tex]\begin{gathered}\end{gathered}[/tex]
10) 8(x-1) = 0
[tex] \implies\tt{8(x - 1) = 0}[/tex]
[tex] \implies\tt{8x - 8 = 0}[/tex]
[tex] \implies\tt{8x = 0 + 8}[/tex]
[tex] \implies\tt{8x = 8}[/tex]
[tex] \implies\tt{x = \dfrac{8}{8}}[/tex]
[tex] \implies\tt{x = 1}[/tex]
[tex]\bigstar \: \: \underline{\boxed{\tt{\blue{x = 1}}}}[/tex]
- Hence, the value of x is 1.
[tex]\begin{gathered}\end{gathered}[/tex]
11) n/2 - 1 = 1
[tex] \longmapsto{\tt{\dfrac{n}{2} - 1 = 1}}[/tex]
[tex] \longmapsto{\tt{\dfrac{n}{2} = 1 + 1}}[/tex]
[tex] \longmapsto{\tt{\dfrac{n}{2} = 2}}[/tex]
[tex] \longmapsto{\tt{n = 2 \times 2}}[/tex]
[tex] \longmapsto{\tt{n = 4}}[/tex]
[tex]\bigstar \: \: \underline{\boxed{\tt{\orange{n = 4}}}}[/tex]
- Hence, the value of n is 4.
[tex]\begin{gathered}\end{gathered}[/tex]
12) 1 = r-3/8
[tex] \implies{\tt{1 = \dfrac{r - 3}{8}}}[/tex]
[tex] \implies{\tt{r - 3 = 1 \times 8}}[/tex]
[tex] \implies{\tt{r - 3 = 8}}[/tex]
[tex] \implies{\tt{r = 8 + 3}}[/tex]
[tex] \implies{\tt{r = 11}}[/tex]
[tex]\bigstar \: \: \underline{\boxed{\tt{\green{r = 11}}}}[/tex]
- Hence, the value of r is 11.
[tex]\rule{300}{2.5}[/tex]
