Answer:
64
Step-by-step explanation:
Let x,y and z represent the product of three positive numbers so
[tex]xyz = 2560[/tex]
We also know z is 60% greater than product of the other two numbers.
Let this be
[tex]z = (1.6)xy[/tex]
We must find the value of z.
Subsitue (1.6)xy for z.
[tex](xy)(xy)(1.6) = 2560[/tex]
[tex]1.6 {x}^{2} {y}^{2} = 2560[/tex]
[tex] {x}^{2} {y}^{2} = 1600[/tex]
[tex]xy = 40[/tex]
Now subsitue this in to any our orginal equation.solve for
[tex]1.6(40) = z[/tex]
[tex]64 = z[/tex]
or we can
[tex]xyz = 2560[/tex]
[tex]40(z) = 2560[/tex]
[tex]z = 64[/tex]
So our z value is 64
