Check the picture below.
so we really have a trapezoid and a rectangle, let's get their area and sum them up.
[tex]\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel ~sides}{bases}\\[-0.5em] \hrulefill\\ h=5\\ a=7\\ b=14 \end{cases}\implies A=\cfrac{5(7+14)}{2}\implies A=\cfrac{105}{2} \\\\\\ \stackrel{\textit{\large areas}}{\stackrel{trapezoid}{\cfrac{105}{2}}~~ +~~\stackrel{rectangle}{(12\cdot 14)}}\implies \cfrac{105}{2}+168\implies \cfrac{241}{2}\implies 120\frac{1}{2}[/tex]
