We have that the the pressure (in atm) of the gas at 50.0 °c is mathematically given as
P2= 2.17 atm
The Gay-Lussac's law states that pressure exerted by gas is directly proportional to the absolute temperature of the gas.
Generally the equation for the Gay-Lussac's law is mathematically given a
P1 / T1 = P2 / T2
Therefore
T1 = 25C
T1= 25 + 273
T1= 298 K
And
T2 = 50C
T2= 50 + 273
T2= 323 K
Therefore
[tex]P2 = \frac{2.00 x 323}{298 }[/tex]
P2= 2.17 atm
Hence, the pressure (in atm) of the gas at 50.0 °c is
[tex]P2 = \frac{2.00 x 323}{298 }[/tex]
P2= 2.17 atm
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