Answer:
1)2x -y+2=0
2)-x +4y +8 = 0
Step-by-step explanation:
Here two equations are given to us and we need to write them in Standard form . The given equations are linear equation in two variables and their Standard form is ,
[tex]\implies ax + by + c = 0 [/tex]
- Where a , b and c are constants .
1) y - 4 = -2(x +3)
Open the brackets on RHS ,
[tex]\implies y - 4 = -2x -6 [/tex]
Transpose all the terms to LHS ,
[tex]\implies 2x - y -4 +6 = 0[/tex]
Add the constant terms ,
[tex]\implies \boxed{ 2x - y +2 =0} [/tex]
Hence the equation in standard form is 2x -y +2=0.
2) y = ¼x -2
Add 2 on both sides ,
[tex]\implies y + 2 = \dfrac{1}{4}x [/tex]
Multiply both sides by 4 ,
[tex]\implies 4y +8 =x [/tex]
Subtract x on both sides,
[tex]\implies \boxed{ -x + 4y + 8 =0}[/tex]
Hence the equation in standard form is -x +4y +8=0 .
