Answer:
x = -6, 10
Step-by-step explanation:
Hi there!
[tex]f(x)=x^2-4x-60[/tex]
Let f(x) = 0:
[tex]0=x^2-4x-60[/tex]
Factor the equation:
[tex]0=x^2-10x+6x-60\\0=x(x-10)+6(x-10)\\0=(x+6)(x-10)[/tex]
The zero-product property tells us that when two terms are multiplied and they equal zero, one of the terms must be zero.
Therefore, either (x+6) or (x110) is equal to 0:
x+6 = 0 ⇒ x = -6
x-10 = 0 ⇒ x = 10
Therefore, the zeros of f(x) are -6 and 10.
I hope this helps!
