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A catcher “gives” with the ball when he

catches a 0.206 kg baseball moving at 18 m/s.

If he moves his glove a distance of 4.14 cm,

what is the average force acting on his hand?

A) Answer in units of kN
B) Repeat for the case in which his glove and
hand move 11 cm.
Answer in units of N.

Respuesta :

sqdancefan

Answer:

  A. 0.806 kN

  B. 0.303 kN

Explanation:

A.

The kinetic energy of the ball is ...

  KE = 1/2mv² = 1/2(0.206 kg)(18 m/s)² = 33.372 J

The work required to reduce this to zero over a distance of 4.14 cm is ...

  W = Fd

  F = W/d = (33.372 J)/(0.0414 m) = 0.806 kN

__

B.

When the distance is 11 cm, the force is ...

  F = (33.372 J)/(0.11 m) = 0.303 kN

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