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A model rocket accelerates upwards at 50m/s^2. Determine the velocity of the model rocket when its fuel is exhausted, 1 second after ignition. You may assume that the rockets initial velocity on the launch pad is zero.

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Answer:

The velocity of model rocket 1 second after ignition is 50 m/s.

Explanation:

time taken(t) = 1 second

initial velocity (u) = 0 m/s

acceleration (a) = 50 m/s²

final velocity (v) = ?

Now,

a = (v-u)/t

or, 50 = (v-0)/1

or, 50 = v

so, v = 50 m/s
  • Acceleration=a=50m/s^2
  • Initial velocity=u=0m/s
  • Time=t=1s
  • Final velocity=v=?

Apply first equation of kinematics

[tex]\\ \tt\hookrightarrow v=u+at[/tex]

[tex]\\ \tt\hookrightarrow v=0+50(1)[/tex]

[tex]\\ \tt\hookrightarrow v=50+0[/tex]

[tex]\\ \tt\hookrightarrow v=50m/s[/tex]

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