The speed of the torpedo fired must be equal to 3.88 times of the speed of the ship.
Sine Law
The Sine Law is [tex]\dfrac{a}{sinA}=\dfrac{b}{sin B}=\dfrac{c}{sinC}[/tex] where, a, b, c are the length of the sides of the triangle and A, B, C are the angles of the triangle.
How to apply sine law?
Submarine is heading towards east and fired a torpedo at [tex]7.4^o[/tex] north-west on a ship traveling at [tex]300^o[/tex] bearing.
According to the given information in the question, the following diagram has been prepared.
[tex]\angle A+\angle B+\angle C=180^o\\\angle A=180-(90+60)-7.4\\\angle A= 22.6^o[/tex]
Now, from sine law-
[tex]\dfrac{AC}{sinB}=\dfrac{AB}{sinC}\\\dfrac{AC}{sin150}=\dfrac{AB}{sin7.4}\\\dfrac{AC}{AB}=\dfrac{0.1288}{0.5}\\\dfrac{AC}{AB}=0.2576\\AB=3.88AC[/tex]
As distance is directly proportional to the time so, the speed of the torpedo fired must be equal to 3.88 times of the speed of the ship.
Learn more: https://brainly.com/question/4372174
#SPJ2
