Respuesta :

fieryanswererft

Answer:

  • its an isosceles triangle
  • not a right angle triangle.

part A:

[tex]\sf AB^2 = (-2-1)^2 + (1+3)^2[/tex]

[tex]\sf AB^2 =25[/tex]

[tex]\sf AB =5[/tex]

[tex]\sf AC^2 = (2-1)^2 + (4+3)^2[/tex]

[tex]\sf AC^2 = 50[/tex]

[tex]\sf AC = \sqrt{50}[/tex]

[tex]\sf AC = 5\sqrt{2}[/tex]

[tex]\sf BC^2 = (2--2)^2 + (4-1)^2[/tex]

[tex]\sf BC^2 = 25[/tex]

[tex]\sf BC = 5[/tex]

use the formula:

short side² + short side² = long side²

( 5√2 )² + 5² = ( 5√2 )²

75 = 50

It's isosceles

  • A(-3,1)
  • B(1,-2)
  • C(4,2)

[tex]\\ \rm\hookrightarrow AB=\sqrt{(-2-1)^2+(1+3)^2}=\sqrt{9+16}=\sqrt{25}=5[/tex]

[tex]\\ \rm\hookrightarrow BC=\sqrt{(2+2)^2+(4-1)^2}=\sqrt{16+9}=5[/tex]

[tex]\\ \rm\hookrightarrow AC=\sqrt{(4+3)^2+(2-1)^2}=\sqrt{50}[/tex]

  • AB=BC

Its isosceles

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