Answer:Hope this Helps :D
For Silicon = \frac{0.1}{0.1}=1
0.1
0.1
=1
For Oxygen = \frac{0.2}{0.1}=2
0.1
0.2
=2
Step 3: Taking the mole ratio as their subscripts.
The ratio of Si : O = 1 : 22.8g of silicon react with 3.2g of oxygen to give a compound, which is shown below. The relative atomic mass of silicon is 28 and of oxygen is 16. What is the value of y in the formula below?Moles of Silicon =\frac{\text{Given mass of Silicon}}{\text{Molar mass of Silicon}}=\frac{2.8g}{28g/mole}=0.1moles
Molar mass of Silicon
Given mass of Silicon
=
28g/mole
2.8g
=0.1moles
Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{3.2g}{16g/mole}=0.2moles
Molar mass of oxygen
Given mass of oxygen
=
16g/mole
3.2g
=0.2moles
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest
number of Answer: The value of 'y' in the formula given is 2
Explanation:
We are given:
The given chemical formula of the compound is SiO_ySiO
y
Mass of Si = 2.8 g
Mass of O = 3.2 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Silicon =\frac{\text{Given mass of Silicon}}{\text{Molar mass of Silicon}}=\frac{2.8g}{28g/mole}=0.1moles
The chemical formula of the compound becomes SiO_2SiO
2
Hence, the value of 'y' in the formula given is 2
