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Determine the number of Mg2+ and PO3−4 ions required to form a neutral ionic compound. Cations and anions

Respuesta :

Answer:

Mg₃(PO₄)₂

Explanation:

Note: The phosphate ion is PO₄³⁻

3Mg⁺² + 2PO₄³⁻ => Mg₃(PO₄)₂

The number of Mg⁺² and PO₄³⁻ ions required to form a neutral ionic compound is:

  • The number cation, Mg⁺² required is 3
  • The number of anion, PO₄³⁻ required is 2

What is a chemical equation?

Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.

The reactants are located on the left side while the products are located on the right side.

Reactants —> Products

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

How to determine the number of cations and anions

To determine the number of cations and anions, needed to produced a neutral compound, we shall write balanced equation. This is illustrated below:

3Mg⁺² + 2PO₄³⁻ --> Mg₃(PO₄)₂

From the balanced equation above, we obtained the following:

  • The number cation, Mg⁺² required is 3
  • The number of anion, PO₄³⁻ required is 2

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