The height of the cannon before it is launched, at t=0, is 58 m.
The equation of motion of the cannon ball is given as;
h(t) = -4.9t² + 19.8t + 58
The initial height of the cannon before it was launched is calculated as follows;
h(0) = -4.9(0) + 19.8(0) + 58
h(0) = 58 m
Thus, the height of the cannon before it is launched, at t=0, is 58 m.
Complete question is below:
The equation that models the path of a cannon ball is h(t) = -4.9t² + 19.8t + 58. What is the height of the cannon before it is launched, at t=0? Remember to include units.
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