Respuesta :

[tex]\\ \rm\Rrightarrow 2sin^2x=1-cosx[/tex]

[tex]\\ \rm\Rrightarrow 2sin^2x=1-1+sin^2x[/tex]

[tex]\\ \rm\Rrightarrow 2sin^2x-sin^2x=0[/tex]

[tex]\\ \rm\Rrightarrow sin^2x=0[/tex]

[tex]\\ \rm\Rrightarrow sinx=0[/tex]

[tex]\\ \rm\Rrightarrow x\in n\pi[/tex]

Answer:

I have done this questions before, the answer is C

Step-by-step explanation: