The radius of the football would be 748299320 times bigger than that of one atom of fluorine.
Atomic radius of fluorine
The atomic radius of a fluorine atom is 147 picometers or 147 x [tex]10^{-12}[/tex] m.
The radius ratio of a football with 11 cm radius and that of one atom of fluorine can be calculated as:
11 x [tex]10^{-2}[/tex]/147 x [tex]10^{-12}[/tex]
= 748299320
Thus, the radius of the football would be 748299320 times bigger than that of one atom of fluorine.
More on the atomic radius of fluorine can be found here: https://brainly.com/question/10330465
