Find the solutions to the equation 102x 11 = (x 6)2 – 2. Which values are approximate solutions to the equation? Select two answers.

Respuesta :

The formula of Sridharacharya is used. Then the values of x are 89.744 and 0.256.

What is a quadratic equation?

It is a polynomial that is equal to zero. Polynomial of variable power 2, 1, and 0 terms are there. Any equation having one term in which the power of the variable is a maximum of 2 then it is called a quadratic equation.

The equation 102x + 11 = (x + 6)² – 2.

We know that the formula

(a + b)² = a² + b² + 2ab

Then we have

102x + 11 = (x + 6)² – 2

102x + 11 = x² + 36 + 12x – 2

102x + 11 = x² + 12x + 34

Take all the terms to the right sides

x² + 12x - 102x + 34 - 11 = 0

                x² - 90x + 23 = 0

Then by the formula, we have

x² - 90x + 23 = 0

[tex]\rm x = \dfrac{-(-90 ) \pm \sqrt{(-90)^2 - 4 *1 * 23}}{2*1}[/tex]

x = 89.744, 0.256

Thus, the values of x are 89.744 and 0.256.

More about the quadratic equation link is given below.

https://brainly.com/question/2263981

Answer:

-9.6

-2.4

Step-by-step explanation: pretty sure those r the answers