The jar below contains 1 striped marble, 2 black marbles, 3 gray marbles, and 4 white marbles. Which will have a probability closest to 1?


A.
drawing a black marble

B.
drawing a striped marble

C.
drawing a white or black marble

D.
drawing a gray or white marble

The jar below contains 1 striped marble 2 black marbles 3 gray marbles and 4 white marbles Which will have a probability closest to 1 A drawing a black marble B class=

Respuesta :

Solution:

  • Probability of getting a striped marble: 1/1 + 2 + 3 + 4 = 1/10 = 10%
  • Probability of getting a black marble: 2/1 + 2 + 3 + 4 = 2/10 = 20%
  • Probability of getting a grey marble: 3/1 + 2 + 3 + 4 = 3/10 = 30%
  • Probability of getting a white marble: 4/1 + 2 + 3 + 4 = 4/10 = 40%

Option A

  • Drawing a Black marble: 2/10 = 20% chance

Option B

  • Drawing a striped marble: 1/10 = 10% chance

Option C

  • Drawing a white or black marble: 4/10 + 2/10 = 6/10 = 60% chance

Option D

  • Drawing a gray or white marble: 3/10 + 4/10 = 7/10 = 70% chance

Option D has the probability closest to 1, as "1 = 10/10 = 100%".

The correct answer is D for all the reasons the previous guy listed