Mo999
contestada

A plane is flying at an altitude of 10,000 feet. How far apart are A and B, to the nearest foot? HINT: In order to use trig, make sure you're working with RIGHT
triangles.

A plane is flying at an altitude of 10000 feet How far apart are A and B to the nearest foot HINT In order to use trig make sure youre working with RIGHT triang class=

Respuesta :

thishigopal

Step-by-step explanation:

draw a vertical line from p to c. there will be 2 right angled triangles pca and PCB.

take tri pca

angle PAC = 49°

tan 49 = pc/ca

1.15 = 10000/ca

ca = 8695.65

take triangle pcb

angle pbc = 25°

tan 25 = pc/bc

0.46 = 10000/bc

bc = 21445.06

AB = 12749.41ft

Otras preguntas