Answer:
I'll assume the equation is h(d) = -(1/1125)d^2 + d
Please check, the (1/1125) term is disturbing.
Step-by-step explanation:
When the ball hits the ground, the height, h(d) is 0. We want the value of d, the distance the ball has travelled horizontally, that would give the function a value of 0.
h(d) = -(1/1125)d^2 + d
0 = -(1/1125)d^2 + d
(1/1125)d^2 - d = 0
Solve using the quadratic equation: I get 0 and - 1125 seconds. I conclude that the factor (1/1125) is incorrect, or some other error in the equation.
The horizontal distance from the point where the ball is hit to the point at which the ball lands on the ground is 1125.
A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.
When the ball hits the ground, the height, h(d) is 0. We need to find the value of d, the distance the ball has traveled horizontally, which would give the function a value of 0.
Solve using the quadratic equation
h(d) = -(1/1125)d^2 + d
0 = -(1/1125)d^2 + d
(1/1125)d^2 - d = 0
(1/1125)d^2 = d
d = 1125
Thus, the horizontal distance from the point where the ball is hit to the point at which the ball lands on the ground is 1125.
Learn more about quadratic equations;
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