The number of moles of each atom present in 5 moles of Cu₃(PO₄)₂ are:
The moles of atom present in 5 moles of Cu₃(PO₄)₂ can be obtained as follow
1 mole of Cu₃(PO₄)₂ contains 3 moles of Cu.
Therefore,
5 moles of Cu₃(PO₄)₂ will contain = 5 × 3 = 15 moles of Cu
1 mole of Cu₃(PO₄)₂ contains 2 moles of P.
Therefore,
5 moles of Cu₃(PO₄)₂ will contain = 5 × 2 = 10 moles of P
1 mole of Cu₃(PO₄)₂ contains 8 moles of O.
Therefore,
5 moles of Cu₃(PO₄)₂ will contain = 5 × 8 = 40 moles of O
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The number of moles of copper, phosphorous and oxygen present in the 5 moles of Cu₃(PO₄)₂ are 15, 20 and 40 respectively.
Stoichiometry of any chemical equation gives idea about the amount of species present before and after the reaction.
Dissociation reaction of Cu₃(PO₄)₂ is shown as below:
Cu₃(PO₄)₂ → 3Cu²⁺ + 2PO₄³⁻
From the stoichiometry of the equation, it is clear that:
1 mole of Cu₃(PO₄)₂ produces 3 moles of copper atom, 2 moles of phosphorous atoms an 8 moles of oxygen atom.
5 moles of Cu₃(PO₄)₂ = produces 3×5=15 moles of Cu
5 moles of Cu₃(PO₄)₂ = produces 2×5=10 moles of P
5 moles of Cu₃(PO₄)₂ = produces 8×5=40 moles of O
Hence required moles of copper, phosphorous and oxygen are 15, 20 and 40 respectively.
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