The balanced equations for the formation of potassium suberate from cyclooctene are;
3KMnO4 + 3C8H18 + 4H2O --> 3C8H17(OH)2 + 2MnO2 + 2KOH and
3C8H14(OH)2 + 6KMnO4 ----> 3KCOO(CH2)6 COOK + 6MnO2 + 6H20
The compound potassium suberate is obtained from cyclooctene. The first step in the process is the oxidation of cyclooctene using potassium permanganate as follows;
3KMnO4 + 3C8H18 + 4H2O --> 3C8H17(OH)2 + 2MnO2 + 2KOH
This is followed by the production of potassium suberate from the reaction equation;
3C8H14(OH)2 + 6KMnO4 ----> 3KCOO(CH2)6 COOK + 6MnO2 + 6H20
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Balanced chemical equation for the formation of potassium suberate from the cyclooctene is 3KMnO₄+3C₈H₁₈+4H₂O→3C₈H₁₇(OH)₂+2MnO₂+2KOH &
3C₈H₁₄(OH)₂+6KMnO₄→3KCOO(CH₂)₆COOK+6MnO₂+6H₂O
Those equation in which number of each entities present on both sids of the given chemical equation is same is known as balanced equation.
Formation of potassium suberate from the cyclooctene will be complete in following two steps:
(1). In first step oxidation of cyclooctene is done by using potassium permanganate.
3KMnO₄ + 3C₈H₁₈ + 4H₂O → 3C₈H₁₇(OH)₂ + 2MnO₂ + 2KOH
(2). In the second step final product is obtained as a result of the oxidation as.
3C₈H₁₄(OH)₂ + 6KMnO₄ → 3KCOO(CH₂)₆COOK + 6MnO₂ + 6H₂O
Hence the balanced chemical reaction for the formation of potassium suberate is discussed above.
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