The current required to plate out 2.96 g of nickel from the solution of Ni²⁺ in 27.12 minutes is 5.95 A
We'll begin by writing the balanced equation showing the number of faraday required to plate nickel. This is given below
Ni²⁺ + 2e —> Ni
Molar mass of Ni = 59 g/mol
Mass of Ni from the balanced equation = 1 × 59 = 59 g
Number of faraday = 2 F
1 faraday = 96500 C
2 faraday = 2 × 96500 = 193000 C
SUMMARY
From the balanced equation above,
59 g of Nickel was deposited by 193000 C of electricity
From the balanced equation above,
59 g of Nickel was deposited by 193000 C of electricity
Therefore,
2.96 g of Nickel will be deposited by = (2.96 × 193000) / 59 = 9682.71 C of electricity
I = Q / t
I = 9682.71 / 1627.2
I = 5.95 A
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The current required to plate out 2. 96 g of nickel from a solution of ni2 in 27. 12 minutes is 5.95 ampere.
Current is a charged particle moving through an electrical conductor.
The equation is [tex]\rm Ni^2^+ + 2e = Ni[/tex]
step 1: calculate the mass of Ni
Molar mass of Ni is 59 g/mol
59 × 1 = 59 g
Step2: calculate the number of Faraday
no. of Faraday is 2F
1 Faraday = 96500 C
then, 2 Faraday is equal to 2 × 96500 = 193000 C
Step 3: calculate the quantity of electricity
59 g of Nickel is deposited by, 193000 C of electricity
So, for 2.96 g of nickel
[tex]\dfrac{2. 96\;g \times 193000}{59} = 9682.71 \;C[/tex]
Step4: calculate the current:
Electricity Q = 9682.71 C
Time = [tex]27.12 \times 60 = 1627.2 \;s[/tex]
To find current
[tex]I = \dfrac{Q}{t} \\\\I = \dfrac{9682.71 }{1627.2}\\I = 5.95 A[/tex]
Thus, the current required is 5.95 ampere.
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