The ka of the weak acid ha, whose conjugate base has kb 2. 9 × 10⁻⁸ is 3.45 × 10⁻⁷.
What is ka value?
Ka value is the equilibrium constant found by the dissociation of acid.
By the equation
[tex]\rm ka \times kb = kw[/tex]
where kb = [tex]2.9 \times 10^-^8[/tex]
kw = [tex]1 \times 10^-^4[/tex]
Now, putting the values in the equation
[tex]1 \times 10^-^1^4 = ka \times 2.9 \times 10^-^8\\\\ka = \dfrac{1 \times 10^-^1^4}{2.9 \times 10^-^8} \\\\ka = 3.45 \times 10^-^7[/tex]
Thus, the ka of the weak acid ha, whose conjugate base has kb 2. 9 × 10⁻⁸ is 3.45 × 10⁻⁷.
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