For a buffer is composed of 33. 80 ml of 0. 164 m acetic acid and 31. 63 ml of 0. 189 m sodium acetate,The volume of HCl is mathematically given as
v1=70.1148mL
Generally, the equation for the Chemical reaction is mathematically given as
HCl+CH3Coo-Na---->CH3CooH+NaCl
Therefore
Mole of HCl=34.37*0.204*10^-3
Mole of HCl=7.011*10^-{-3}
In conclusion
M1v1=m2v2
Therefore
[tex]v1=\frac{m2v2}{m1}\\\\v1=\frac{7.011*10^-{-3}}{0.1}[/tex]
v1=70.1148mL
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70.114 ml of 0. 100 m HCl can be added before the buffer capacity is reached
Volume is the space occupied by a three-dimensional object.
The chemical reaction is
[tex]\rm HCl+CH_3Coo-Na---- > CH_3CooH+NaCl[/tex]
step1, calculate the moles of HCl
[tex]34.37 \times0.204\times 10^-3[/tex]
[tex]\rm Moles\; of\; HCL \;7.011\times 10^{-3}[/tex]
The given Volume 1 is 33.80 ml
The given volume 2 is 31.63 ml
By the formula, [tex]M_1V_1=M_2V_2[/tex]
Putting the values in the equation
[tex]0.164 \times 33.80 = 100 \times V_2\\\\V_2 = 70.114 ml.[/tex]
Thus, the final volume is 70.114 ml.
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v1=70.1148mL
