For two planets orbiting a star in a distant galaxy, having the first semimajor axis of 150 x 10^6 km, the period of the second plane is mathematically given as
T=2.2earth year
Generally, the equation for the time period is mathematically given as
[tex]T^{2} \appox a^{3}[/tex]
Therefore, for planet one
[tex]1^2\approx (150 x 10^6)^3[/tex]
In conclusion, For planet 2
T^2=(250/150)^3
T=√4.632
T=2.2earth year
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The period of the second planet for two planets circling a star in a faraway galaxy with a first semimajor axis of 150× 10⁶ km. The time period of the planet will be 2.2 earth years.
The time period of the revolution is the time required to complete one revolution. It is guven by T. It is measured in seconds.
The equation of the time period is found as;
[tex]\rm T = \frac{250}{150} ^3 \\\\ T= \sqrt{4.632} \\\\ T=2.2 \ earth \ year[/tex]
Hence the time period of the planet will be 2.2 earth years.
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