[tex]\sf\huge\underline{Given:-}[/tex]
Area of the square field [tex]\sf{= 625 m^2}[/tex]
[tex]\sf\huge\underline{To\: Find:-}[/tex]
[tex]\rightarrow[/tex] Perimeter of the square garden.
[tex]\sf\huge\underline{Formula \:Used:-}[/tex]
Area of square [tex]\sf{= side^2}[/tex]
Perimeter of square [tex]\sf{= 4×side}[/tex]
[tex]\sf\huge\underline{Solution:-}[/tex]
As we know,
[tex]\rightarrow[/tex] Area of square [tex]\sf{= side^2}[/tex](putting the given value of area)
[tex]\rightarrow[/tex] [tex]\sf{Side^2}[/tex] [tex]\sf{= 625}[/tex]
[tex]\rightarrow[/tex] [tex]\sf{Side}[/tex][tex]\sf{= \sqrt{625}}[/tex]
[tex]\rightarrow[/tex][tex]\sf{Side}[/tex][tex]\sf{= 25cm}[/tex]
So, From here we got the side of the square garden that is, 25cm.
Now,
[tex]\rightarrow[/tex]Perimeter of square [tex]\sf{= 4×side}[/tex](Putting the value of side)
[tex]\rightarrow[/tex] Perimeter of square [tex]\sf{= 4×25}[/tex]
[tex]\rightarrow[/tex]Perimeter of square [tex]\sf{= 100cm}[/tex]
Therefore, perimeter of the square garden = 100cm.
