Answer:
x=-2, y=-9
Step-by-step explanation:
Given that:
[tex]\begin{bmatrix}3x+y=-15\\ 2x-3y=23\end{bmatrix}[/tex]
Solution:
[tex]\mathrm{Isolate\;x\;for\;3x+y=-15:x=\frac{-15-y}{3}}[/tex]
[tex]\mathrm{Substitute\:}x=\frac{-15-y}{3}[/tex]
[tex]\begin{bmatrix}2\cdot \frac{-15-y}{3}-3y=23\end{bmatrix}[/tex]
Simplify to:
[tex]\begin{bmatrix}\frac{-30-11y}{3}=23\end{bmatrix}[/tex]
[tex]\mathrm{Isolate\;y\;for\;\frac{-30-11y}{3}=23:y=-9}[/tex]
[tex]\mathrm{For\:}x=\frac{-15-y}{3}[/tex]
[tex]\mathrm{Substitute\:}y=-9[/tex]
[tex]x=\frac{-15-\left(-9\right)}{3}[/tex]
Solve:
[tex]x=-2[/tex]
Hence the answer is:
[tex]x=-2,\:y=-9[/tex]
~lenvy~
