The amount of heat energy lost by the 100 mL of water when it all freezes is 33400 J
Data obtained from the question
How to determine mass of water
- Volume of water = 100 mL
- Density of water = 1 g/mL
Mass = Density ×Volume
Mass of water = 1 × 100
Mass of water = 100 g
How to determine the heat
- Mass of water = 100 g
- Heat of fusion (ΔHf) = 334 J/g
Q = m × ΔHf
Q = 100 × 334
Q = 33400 J
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