Respuesta :

The sequence an = 1 + (-3/7)^n is neither an arithmetic progression nor a geometric progression

The first ten terms of the sequence are 0.5714, 1.1837, 0.9213, 1.0337, 0.9855, 1.0062, 0.9973, 1.0011, 0.9995 and 1.0002

How to determine the first ten terms?

The nth term of the sequence is given as:

an = 1 + (-3/7)^n

The first ten terms are calculated as follows:

a1 = 1 + (-3/7)^1 = 0.5714

a2 = 1 + (-3/7)^2 = 1.1837

a3 = 1 + (-3/7)^3 = 0.9213

a4 = 1 + (-3/7)^4 = 1.0337

a5 = 1 + (-3/7)^5 = 0.9855

a6 = 1 + (-3/7)^6 = 1.0062

a7 = 1 + (-3/7)^7 = 0.9973

a8 = 1 + (-3/7)^8 = 1.0011

a9 = 1 + (-3/7)^9 = 0.9995

a10 = 1 + (-3/7)^10 = 1.0002

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