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Write an equation in slope-intercept form for the line that passes through (6,6) and is
perpendicular to the line described

Write an equation in slopeintercept form for the line that passes through 66 and is perpendicular to the line described class=

Respuesta :

ghanami

Answer:

Step-by-step explanation:

Solution :

Hello:

an equation   for the line is : y =mx +b    (m: is a slope )

perpendicular to the line described by : y = 2/3 x -2

So : product for two slopes = -1   means : m×2/3=-1

m = -3/2

now : y = -3/2 x+b

but this line :

through the point (6,6) : 6 =(-3/2)(6)+b....... b=15

conclusion :

the equation is : y = -3/2x +15

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