The z-statistic is 1. 68, so the null hypothesis cannot be rejected.
The expected value of the amount of average snowfall for over 30 years is 86.7 inches with a standard deviation of 40.4 inches.
To verify if this particular trend continues, we must check the significance value of the amount snowfall for the past four years.
Given that the snowfall for past years are as follows: 115.7 inches, 62.9 inches, 168.5 inches, and 135.7 inches.
Thus the mean of the sample would be: (115.7 + 62.9 + 168.5 + 135.7)/4 = 120.7 inches.
To compute for the z-score,
we have z-score = (x – μ) / (σ / √n)
where x is the computed/measured value,
μ is the expected mean, σ is the standard deviation,
and n is the number of samples.
Using the information we have,
z-score (z) = (120.7 - 86.7) / (40.4/ √4) = 1.68
In order to reject the null hyptohesis our probability value must be less than the significance level of 5%. For our case, since z = 1.68, P-value = 0.093 > 0.05.
Hence The z-statistic is 1. 68, so the null hypothesis cannot be rejected.
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Answer:
B. The z-statistic is 1.68, so the null hypothesis cannot be rejected.
Step-by-step explanation:
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