Recall that in a 30 – 60 – 90 triangle, if the shortest leg measures x units, then the longer leg measures xStartRoot 3 EndRoot units and the hypotenuse measures 2x units. (150StartRoot 3 EndRoot – 75π) ft2 (300 – 75π) ft2 (150StartRoot 3 EndRoot – 25π) ft2 (300 – 25π) ft2.

Respuesta :

The area of the shaded region is  [tex]\rm (150\sqrt{3} \ - 75\pi ) \ feet^2[/tex] option first is correct.

It is given that a circle is inscribed in a regular hexagon with sides of 10 feet.

It is required to find the shaded area (missing data is attached shown in the picture).

What is a circle?

It is defined as the combination of points that and every point has an equal distance from a fixed point ( called the center of a circle).

We have a hexagon with a side length of 10 feet.

We know the area of the hexagon is given by:

[tex]\rm A = \frac{3\sqrt{3} }{2} a^2[/tex]  where a is the side length.

[tex]\rm A = \frac{3\sqrt{3} }{2} 10^2[/tex] ⇒ [tex]150\sqrt{3}[/tex] [tex]\rm feet^2[/tex]

We have the shortest length = x feet and from the figure:

2x = 10

x = 5 feet

The radius of the circle r = longer leg

[tex]\rm r = x\sqrt{3} \Rightarrow 5\sqrt{3}[/tex] feet

The area of the circle a = [tex]\pi r^2[/tex]  ⇒ [tex]\pi (5\sqrt{3} )^2 \Rightarrow 75\pi \ \rm feet^2[/tex]  

The area of the shaded region = A - a

[tex]\rm =(150\sqrt{3} \ - 75\pi ) \ feet^2[/tex]

Thus, the area of the shaded region is  [tex]\rm (150\sqrt{3} \ - 75\pi ) \ feet^2[/tex]

Learn more about circle here:

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Answer:

option A

Step-by-step explanation: