1. Simplify the quadratic equation into its standard form
Formula : ax^2+bx+c=0
Subtract from both sides:
x^2-10x+25=51
x^2-10x+25-51=0
x^2-10x-26=0
Use the standard form, ax^2+bx+c=0, to find the coefficients of our equation.
x^2-10x-26=0
a=1
b=-10
c=-26
The quadratic formula gives us the roots for ax^2+bx+c=0, in which a, b and c are numbers (or coefficients), as follows :
x=(-b±sqrt(b^2-4ac))/(2a)
to get the result :
x=(10±sqrt(204))/2
Simplify 204 by finding its prime factors:
The prime factorization of 204 is 2^2*3*17
x_2=-2.141
