y=-2x+5
First of all we need to determine the slope of the line perpendicular to y = 1/2x - 5 .
The slopes of perpendicular lines are opposite reciprocals.
So we take 1/2 , turn it over , and change it's sign :
[tex]^1/_2\:\:\:--- > ^2/_1\:\:\:--- > 2\:\:\:--- > -2[/tex]
The slope of the line perpendicular to y = 1/2x-5 is -2 .
Since we're also given a point that the line crosses , we can write the line's equation in point - slope form :
y-y₁=m(x-x₁)
y-7=-2(x-(-1)
y-7=-2(x+1)
Now convert to slope intercept :
y-7=-2x-2
add 7 on both sides :
[tex]\footnotesize\text{hope\:helpful}[/tex]
