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One positve and one negative charhe jave a force of -5. 00 N between them. If the force changed to -170 N , by what factor did the distance between them change

Respuesta :

Answer:

The distance is shortenend by factor .1715

Explanation:

5 n  = 1/r^2

sqrt (1/5) = r

170 n  = 1 / ( x sqrt(1/5))^2

(xsqrt 1/5)^2 = 1/170

x sqrt 1/5  = .076696

x = .1715    

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