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A 53.8 g sample is burned in a bomb calorimeter. If the temperature rose from 32.0 oC to 56.0 oC and the heat capacity of the calorimeter is 13.3 kJ/oC, what is the value of ΔHrxn (in kJ/mole of sample)? The molar mass of the sample is 56.23 g/mol.

Respuesta :

mickymike92

Based on the heat absorbed by the calorimeter, the heat of reaction, ΔHrxn is 333.5 kJ/mol

What is the heat evolved by the sample?

The heat evolved or given out by the sample is the equal to the amount of heat absorbed by the calorimeter.

The heat absorbed by calorimeter is given as:

  • Heat = specific heat capacity × temperature difference

Heat = 13.3 × (56.0 - 32.0)

Heat evolved = 319.2 kJ

Moles of sample reacted = 53.8/56.23 = 0.957

ΔHrxn = 319.2 kJ/0.957 moles = 333.5 kJ/mol

Therefore, the heat of reaction, ΔHrxn is 333.5 kJ/mol.

Learn more about heat of reaction at: https://brainly.com/question/25758173

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