Explanation:
The formula for work is
[tex]w = |f| |d| \cos(x) [/tex]
where x is the angle between the displacement and force.
F is the force that is currently being active.
D is the displacement.
We only want our force and displacement to be positve so we use the absolute value sign.
Since the rocket and the displacement is both upwards, the signs. between them is 0.
So since
[tex] \cos(0) = 1[/tex]
We can just use that
[tex]w = |f| |d| [/tex]
First, we covert km to m.
[tex]144 \: km \times \frac{1000 \: m}{1 \: km} = 144000 m[/tex]
Now, we can multiply.
[tex]w = 14400 \: km \: \times (6.27 \times 10 {}^{5} )[/tex]
[tex]w = (1.44 \times 10 {}^{5} ) \times (6.27 \times 10 {}^{5} )[/tex]
[tex]w = 9.0288 \times 10 {}^{10} [/tex]
N times Meters = J so our answer is
[tex]w = 9.0288 \times 10 {}^{10} \: j[/tex]
