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How many milliliters of a 0.1000 M NaOH solution would be needed to neutralize a 1.0000-g sample of potassium hydrogen phthalate (KHC8H4O4) to a phenolphthalein endpoint, according to the following balanced equation?
KHC8H4O4(s)+NaOH(aq)------> KNaC8H4O4(aq)+H2O(l)

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Answer: 2) 2HCl(sq) + CaCO3(s) CaCl2(sq) + CO2(g) + H2O (l) No of moles of CaCO3 = amount of the CaCO3 (g)/mw of CaCO3 (g/mole)= 0.8085 g/100 g/mole = 0.008085

Explanation:

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