in the following reaction 10.5 moles of chromium are added to 6.8 moles of oxygen find limiting an excess reactants and answer the questions that follow.

in the following reaction 105 moles of chromium are added to 68 moles of oxygen find limiting an excess reactants and answer the questions that follow class=

Respuesta :

Answer:

If 3.4 moles of carbon dioxide (CO2) form at the end of the reaction, 1.7 moles of oxygen gas

(02) and 3.4 moles of carbon monoxide (CO) entered the reaction

Explanation:

The rule of three or is a way of solving problems of proportionality between three known

values and an unknown value, establishing a relationship of proportionality between all of

them. That is, what is intended with it is to find the fourth term of a proportion knowing the

other three. Remember that proportionality is a constant relationship or ratio between different

magnitudes.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so

does the other (or when one magnitude decreases, so does the other), the direct rule of three

must be applied. To solve a direct rule of three, the following formula must be followed:

ab

cx

So

C*b

T =

a

In this case, it is possible to use the reaction stoichiometry of the reaction (that is, the

relationship between the amount of reagents and products in a chemical reaction) and the rule

of three to calculate the quantities of moles requested:

.

,

If by stoichiometry 2 moles of CO2 are formed by 1 mol of O2, if 3.4 moles of CO2 are

formed, how many moles of O2 are needed?

molesofo2 = 3.42

=

moles of O2=1.7 moles

• If by stoichiometry 2 moles of CO2 are formed by 2 moles of CO, if 3.4 moles of CO2 are

formed, how many moles of CO are needed?

molesof CO =

=

3.4*2

2

moles of CO=3.4