Ammonia undergoes combustion with oxygen to produce nitric oxide and water. The volume of the oxygen required to react with 720 ml of ammonia is 900 ml.
Volume is the area occupied by the substance and is the ratio of the mass to the density.
At STP, 1 mole of gas occupies 22.4 L of volume
Given,
Volume of ammonia reacted = 0.720 L
The combustion reaction is shown as,
[tex]\rm 4NH_{3} + 5O_{2} \rightarrow 4NO +6H_{2}O[/tex]
From the stoichiometry of the reaction, it can be said that,
[tex](4 \times 22.4)[/tex] L of ammonia reacts with [tex](5 \times 22.4)[/tex] L of oxygen gas.
So, 0.720 L of ammonia will react with:
[tex]\dfrac{ (5 \times 22.4)}{(4 \times 22.4)} \times 0.720 = 0.9 \;\rm L[/tex]
Therefore, the volume of oxygen required is 900 mL.
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