The total kinetic energy of a 5-kg hoop with a radius of 0. 5 m when it rolls without slipping at 4. 0 m/s is 80 Joules.
The kinetic energy is the ability to do work by virtue of its motion.
The mass of the hoop is 5 kg, the radius of the hoop is 0.5 m and the speed with which it is rolling is 4.0 m/s.
The angular speed of the hoop is
ω = v / r
ω = 4 / 0.5 = 8 rad/s
The moment of inertia of the hoop is I = m r² / 2
The kinetic energy of the rolling object is the addition of translation and rotational kinetic energy.
K.E = 1 / 2(mv²) + = 1 / 2(Iω²)
Substituting the values into the above equation and solving, we get the total kinetic energy.
K.E = 40 + 40 = 80 Joules
Thus, the total kinetic energy is a rolling hoop is 80 Joules.
Learn more about kinetic energy.
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